Question

In the given figure ∠CAB: ∠BAD = 1:2, find all internal angles of Δ ABC

Answer 1

Answer:

Let kbe the constant of proportionality

∠CAB=k

∠BAD = 2k

k+2k+69=180

3k= 111

k= 37

By external angle property,

37= x + x + 13

24=2x

x=12°

Angle B= 12

Angle C = x +13 = 12 +13 =25

Angle A = 180-37= 143

Answer 2

Answer:

answer to the above question