In the given figure DE parallel to BC, , AE= 1.8cm, EC=5.4cm&
DB=7.2 cm then find the AD
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Answer:
It is given that, In ΔABC and DE∥BC.
We have to find AD=?
Since,
DB=7.2c.m.
AE=1.8c.m.
EC=5.4c.m.
So, We know that (using Thales Theorem)
DB
AD
=
CE
AE
Then,
7.2
AD
=
5.4
1.8
AD=
5.4
1.8×7.2
AD=
3
7.2
AD=2.4 c.m.
Hence it is complete solution.
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