In the given figure, find BAC
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raj744:
it will be 110 degree
is it not given that it is a semi circle
as the line don't cross from the centre
yes ans is 110
hmm
hmm
what
means ok
?..
OK k
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May this will help you
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Hey, there is ur ans. (^.^)= in triangle EDC= 130 is exterior angle so, angle ECD + angle EDC =130.
THEREFORE, angle EDC= 130-20= 110.-(1)
BUT, angle BAC = angle BDC. (ANGLE IN THE SAME SIFE OF SAME CHORD ARE EQUAL)-(2)
FROM 1 AND 2
angle BAC = 110..
I HOPE IT WILL HELP U.
PLZ MARK AS BRILLIANT
THEREFORE, angle EDC= 130-20= 110.-(1)
BUT, angle BAC = angle BDC. (ANGLE IN THE SAME SIFE OF SAME CHORD ARE EQUAL)-(2)
FROM 1 AND 2
angle BAC = 110..
I HOPE IT WILL HELP U.
PLZ MARK AS BRILLIANT
Brilliant
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