Question

In the given figure, find the area of quadrilateral ABCD ​

Answer 1

This question is simple.

Given- In triangle ADC

AD= 9cm, CD= 12cm and AC=??

By pythagoras theorm

( Hyp)^2 = (b)^2 + (alt)^2

(Hyp)^2 = (12)^2 + (9)^2

(Hyp)^2 = 144 + 81

(Hyp)^2 =225

(Hyp) = 15cm

Now, let's take triangle ABC

Again by pythagoras theorm -

(17)^2 = (15)^2 + (B)^2

289 = 225 + B^2

289- 225 = B^2

64 = B^2

B = 8cm

Now, area of quadrilateral ABCD =area of triangle ACD+ABC

= 1/2 * B*H + 1/2 * B*H

=1/2* 8* 15 + 1/2 *9*12

After solving it-

= 60+54

=114cm^2 is the area of quadrilateral ABCD

HOPE this answer will help and satisfy you!!!!

Answer 2

Answer:

144

Step-by-step explanation:

both pics are same hzhdhdhh