in the given figure find x and y no spams
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Answer:
/_ABC = 90° [Angle in a semicircle]
Since /_ABC is 90°(proved), /_CBE = 90° [Linear pair]
x = /_CBE + 20° [Exterior angle property]
x = 110°
Construction: Join OB
In Triangle ABO:
/_OAB = /_ABO = 30° [OA = OB, radii of same circle. Opposite angles of equal sides]
/_BOC = /_OAB + /_ABO [Exterior angle property]
=> /_BOC = 60°
/_BOC = 2/_BDC [Angle on centre is double of the angle on the circle]
/_BDC = 30°
In Triangle BCD:
x + /_BDC + y = 180° [Angle Sum Property of a triangle]
y = 180 - 110 - 30
y = 40°
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