in the given figure, if ABllCD, then x=?
(a)100°
(b)105°
(c)110°
(d)115°
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Answer:
100°
Step-by-step explanation:
Let us draw a line segment PQ through P parallel to AB as well as CD.
AB||PQ,AP transversal
BAP=132°
APQ=(180-132)°=48°
PQ||CD,PC transversal
QPC=(148-48)°=100°
x=100°
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