Question

in the given figure if o is the centre of a circle. AB is a chord and the tangent AC at A makes an angle 65 degree with AB, then find the Angle AOB

Answer 1

angle AOC = 90° (Radius is perpendicular at point of contact with tangent)
angle BAC = 65°
therefore , angleOAB = 90°- 65° = 25°
Now in triangle AOB ,
AO = BO (radius)
therefore angle OAB = angle OBA
therefore angle AOB = 180°- (25°× 2)= 130°

Hope it helps!

Answer 2

The answer of question is 130degree.