Question

in the given figure kt bisects <ike and <ite prove that ∆kit congruent to ∆ket
FIGURE IS GIVEN ABPVE​

Answer 1

Answer:

Given ABCD a kite, with AB = AD and CB = CD , the following things are true. Diagonal line AC is the perpendicular bisector of BD. ... Triangle ABC is congruent to triangle ADC.

Answer 2

Given ABCD a kite, with AB = AD and CB = CD, the following things are true.

Diagonal line AC is the perpendicular bisector of BD.The intersection E of line AC and line BD is the midpoint of BD.Angles AED, DEC, CED, BEA are right angles.Triangle ABC is congruent to triangle ADC.Consequently angle ABC = angle ADC.Line AC bisects angles BAD and BCD

Two statements are in bold type, because those statements include the others, from the definitions or perpendicular bisector and congruence of triangles. (Of course to prove the bold statements, one may have to prove some of the others first.