In the given figure, LM || CB and LN || CD. Prove that AM/AB = AN/AD
Attachments:
Answers
Answered by
19
hope this helps you....
Attachments:
Answered by
15
Given :
In ∆ACB , LM//CB
and
In ADC , NL // DC
R.T.P : AM/AB = AN/AD
Proof :
I. ∆ACB , LM//CB
=> AM/AB = AL/AC ---( 1 )
[ Thales theorem ]
In ∆ADC , NL//DC
=> AN/AD = AL/AC ----( 2 )
[ Thales theorem ]
From ( 1 ) and ( 2 ) , we get
AM/AB = AN/AD
☺️
In ∆ACB , LM//CB
and
In ADC , NL // DC
R.T.P : AM/AB = AN/AD
Proof :
I. ∆ACB , LM//CB
=> AM/AB = AL/AC ---( 1 )
[ Thales theorem ]
In ∆ADC , NL//DC
=> AN/AD = AL/AC ----( 2 )
[ Thales theorem ]
From ( 1 ) and ( 2 ) , we get
AM/AB = AN/AD
☺️
Similar questions