Question

in the given figure of projectile

Answer 1

"The basic formula used in the projectile is,

Maximum height reached, H = vo^2 * sin^2 theta/ 2 * g

Since y is not maximum height here, you can determine the value of y with the help of velocity and time formula that will give you the value

Y = [x1 * x2 / x1 + x2] tan theta

"

Answer 2

$\underline{\large\bf{\mathfrak{Hello!}}}$

To solve this question you need to understand the projectile and understand the equation of trajectory.

For a well explained answer please refer to the attachment.

$\boxed{y = [\frac{x_{1} x_{2} } {x_{1} +x_{2} }]tan\theta}$

$\bf{\mathfrak{Hope \: this \: helps...:)}}$