Question

in the given figure PQ =QR and RQP=86 PC AND CQ ARE TANGENTS TO THE CIRCLE WITH CENTRE O. CALCULATE THE VALUES OF QOP AND QCP
CORRECT ANSWER WILL BE GIVEN BRAINLIEST
WORST ANSWERS ARE STRICTLY NOT ALLOWED

Answer 1

Answer:

QOP = 94, QCP = 86

Step-by-step explanation:

PQ = QR

Thus, ∠P = ∠R

 Also, ∠P + ∠Q + ∠R = 180  ( angle sum )

        ∠Q = 86

Thus, 2 ∠P = 180 - 86 =94

thus ∠P = 47 = ∠R

∠CQP = ∠QRP ( alternate segment theorem  since  CQ is tangent to circle )

Thus ∠CQP = 47 = ∠CPQ ( SInce CP=CQ, tangent segment theorem )

Thus, in triangle CPQ, ∠C + ∠P + ∠Q = 180

Thus, ∠C = 180 - 2 * 47 = 180 - 94 = 86

Thus in Quad OPCQ, ∠P + ∠Q = 180 ( Tangent are perpendicular to radius )

Hence it is cyclic

Thus ∠O + ∠C = 180

That is ∠O = 180 - 86 = 94

Hope it Helps

MARK AS BRAINLIEST Plzz

Answer 2

Answer is in the attachment.

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