In the given figure PT is a tangent to circle with centre O if QR =6cm PR=8cmand triangle PRQis similar to TPQ. Find OT/PT
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Qr=6cm
PR=8cm
If Qr is 6 cm then Ot is =QR
PT =8 CM
PR=8cm
If Qr is 6 cm then Ot is =QR
PT =8 CM
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