in the given figure, ST is parallel to RQ, PS=3cm and SR=4cm. Find the ratio of the area of Triangle PST to the area of triangle PRQ
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sorry ans will be 7:49
deeksha2693:
please try to give Complete solution
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ST II RQ
area of triangle PST / area of triangle PRQ = PS^2/PR^2
= 3^2/7^2 (PR=PS+SR=3+4=7)
= 9/49
So the ratio between the triangles are 9:49
area of triangle PST / area of triangle PRQ = PS^2/PR^2
= 3^2/7^2 (PR=PS+SR=3+4=7)
= 9/49
So the ratio between the triangles are 9:49
Dude why hv u squared the two terms?
the ratio of the areas of two similar triangles is equal to the square of the ratios of their corrseponding sides .
yeah! ✌
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