Question

In the given figure triangles ABC and DCB are right angled at A and D respectively and AC congruent D. Prove that triangle ABC congruent to triangle DCB.​

Answer 1

ac=db

to prove

ΔABC = ΔDCB

Proof,

In ΔABC and ΔDCB:

AC = DB (given) BC = BC

(common) ∠CAB = ∠BDC = 90

From the RHS congruence property,

ΔABC ≅ ΔDCB