Math, asked by pavanikapavarapu, 18 days ago

what is the value of (3x-5y)^3 -(5x-2y)^3 +(2x+3y)^3​

Answers

Answered by Brainlygirl11
0

Let's simplify step-by-step.

(3x−5y)³−(5x−2y)³+(2x+3y)³

Distribute:

=27x³+−135x²y+225xy²+−125y³+−125x³+150x2y+−60xy²+8y³+8x³+36x²y+54xy²+27y³

Combine Like Terms:

=27x³+−135x²y+225xy²+−125y³+−125x³+150x²y+−60xy²+8y³+8x3+36x2y+54xy²+27y³

=(27x3+−125x3+8x3)+(−135x2y+150x2y+36x2y)+(225xy²+−60xy²+54xy²)+(−125y³+8y³+27y³)

=−90x3+51x2y+219xy²+−90y³

Answer:

=−90x³+51x2y+219xy²−90y³

Answered by SandhraCherukuri
0

Answer:

- 90x³ - 90y³ + 43x²y + 219y²x

Explanation

(3x - 5y)^3 - (5x - 2y)^3 + (2x + 3y)^3

= 27x³ - 125y³ - 135x²y + 225y²x - 125x³ + 8y³ - 60y²x + 150x²y + 8x³ + 54y²x + 28x²y + 27y³

grouping the terms

= 27x³ - 125x³ + 8x³ - 125y³+ 8y³+ 27y³ - 135x²y + 150x²y + 28x²y + 225y²x - 60y²x + 54y²x

= - 90x³ - 90y³ + 43x²y + 219y²x

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