In the given figure, two chords AB and CD of
a circle with centre O, with centre O are such that OP and OQ the perpendicular from centre to the chords are equal,
show that AB parallel to CD
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WE ASSUME THAT AB IS PARALLEL TO CD.
AND PQ IS THE TRANSVERSAL
<APQ+<QPA=180
THERE FORE AB IS PARALLEL TO CD .
or
as the sum is 180 we can directly say that they are parallel to each other
MARK IT AS BRAINLEST
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