Question

In the given figure two circles intersects each other at
points S and R. Their comman tangent PQ touches the
circle at points P and Q. Prove that:
PRQ+ ZPSQ = 180°​

Answer 1

Step-by-step explanation:

REF.Image.

∠PRQ+∠PSQ=180

∘

∠SPQ=

2

1

m(arcPR)

∠SQR=

2

1

m(arcPQ)

Inscribed angle

∠PSQ+∠PQS+∠SQP=180

∘

(sum of all angle)

∠SQR=

2

1

×m(arcSRQ) also

∠SPQ=

2

1

m(arcSRP)

But

∠PSQ=1/2∠PRQ

arcPR+arcRQ=180

∘

also

∠PRQ+∠PSQ=180

∘

solution