Question

In the given figure value of x for which DE | BC is ​

Answer 1

Answer:

By BPT Theorem,

AD/DB=AE/EC.

x+3/3x+19=x/3x+4

x(3 X + 4)+3(3x+4)=x(3x+19)

3x^2+4x+9x+12= 3x^2+19x (cross multiplication method)

3x^2-3x^2+13x-19x=-12

-6x=-12

x=-12/-6=→ 2. (becoz minus and minus gives Plus)

so the value of x = 2.

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