Question

In the given figure,we have PQ = SR and PR = SQ prove that :
1) ∆PQR = ∆SRQ
2) <PQR = <SRQ​

Answer 1

in ∆PQR and ∆SRQ

QR=RQ(common)

PQ=SR(given)

PR=SQ(given)

∆PQR=∆SRQ (by SSS congruency)

By CPCT anglePQR = angleSRQ

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Answer 2

Answer:

In ΔPQR and ΔSRQ,

PQ = SR-------(given)

PR = SQ-------(given)

QR = QR------(common side)

∴ ΔPQR ≅ ΔSRQ by SSS congruence.

∠PQR = SRQ by CPCT.

Hence Proved.