Question

In the parallelogram ABCD, the bisector angle A and angle B meets at O. Find AOB?​

Answer 1

Angle A +angle B =180 (co interior)

1/2 angle A +1/2 angle B =90 .............1

So in triangle AOB,

angle AOB + 90 =180 (from equation1)

Hence, angle AOB =90.

Answer 2

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ANSWER IN THE ATTACHMENT