In the reaction C3H8 + O2 --> CO2 + H2O, if 50.0g of O2 is available for 25.0 g of propane (C3H8), which reactant is in excess?
Answers
Answered by
0
Answer:
using stoichiometry coefficient of propane is 1 and o2 is also 1 hence amount of their weight is 1:1 but given is 50 gram O2 and 25 gram Propane causes if propane is completely burn put 25 GRAM O2 still remain causing O2 as excess reactant and propane is limitting reactant which controls reaction .
Similar questions
Biology,
8 hours ago
English,
8 hours ago
Math,
8 hours ago
Math,
16 hours ago
Social Sciences,
16 hours ago