In the reaction
CH₃ ≡ C⁻ - Na⁺ + (CH₃)₂CH - Cl →?
the product formed is :
(a) propene (b) propyne
(c) propyne and propene (d) 4-methylpentyne-2
Answers
Answered by
0
Explanation:
The product formed is propene
Answered by
0
The product formed is :
Reaction : CH₃ ≡ C⁻ - Na⁺ + (CH₃)₂CH - Cl →
Reaction would proceed with removal of Na+ from CH₃ ≡ C⁻ - Na⁺ and Cl- from (CH₃)₂CH - Cl , forming NaCl molecule.
Thus further reaction is,
CH₃ ≡ C⁻ - Na⁺ + (CH₃)₂CH - Cl → CH₃ ≡ C⁻ + (CH₃)₂CH⁺ + NaCl →
CH₃ ≡ CCH(CH₃)₂
Final product is none of the above following options. It is 3-methyl butyne.
Similar questions