Question

In the reaction, CrO5 + H2SO4------> Cr2(SO4)3 + H2O + O2 one mole of CrO5 will liberate how many moles of O2?

Answer 1

Balancing given equation 2CrO5+3H2SO4------->Cr2(SO4)3+ 3H2O+7/2O2
As 2 moles of CrO5 is giving 7/2 moles of O2.
So one mole of CrO5 we will give 7/4 moles of O2.
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Answer 2

Answer : One mole of $CrO_5$ liberated the number of moles of $O_2$ will be, 1.75 moles.

Solution :

The balanced chemical reaction is,

$4CrO_5+6H_2SO_4\rightarrow 2Cr_2(SO_4)_3+7O_2+6H_2O$

From the balanced chemical reaction, we conclude that

As, 4 moles of $CrO_5$ react to give 7 moles of $O_2$

So, 1 mole of $CrO_5$ react to give $\frac{7}{4}=1.75moles$ of $O_2$

Therefore, one mole of $CrO_5$ liberated the number of moles of $O_2$ will be, 1.75 moles.