In the triangle abc anglebac=90degree ad perpendicular to bc ab =15 cm and bd=9cm then the angle of bd is what
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here AD is perpendicular to BC
so, angle D =90°
and AD bisects angle A =90÷2=45°
=>angle B=180-(90+45)=45°
so, angle D =90°
and AD bisects angle A =90÷2=45°
=>angle B=180-(90+45)=45°
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