In trapezium PQRS side PQ|| side SR,AR= 5 AP, AS= 5 AQ then prove that SR=5 PQ
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Answer:
Given
side PQ || side SR
AR = 5 AP
AS = 5 AQ
To prove : SR = 5 PQ
Proof : In ΔAPQ and ΔARS
∠PAQ=∠RAS (Vertically opposite angles) ∠PAQ=∠RSA (Alternate angles , side PQ || side SR and QS is a transversal line)
By AA test of similarity
ΔAPQ∼ΔARS
SR
PQ
=
AR
AP
(Corresponding side are proportional)
⇒
SR
PQ
=
5
1
(AR=5AP)
⇒SR=5PQ
Hence proved.
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