In triangle abc ,ab =9cm bc=12cm bd is the bisector of angle b . What is the relation between the areas of triangle abd and triangle bcd ?
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GIVEN:
In triangle abc ,ab =9cm bc=12cm bd is the bisector of angle b
WHAT TO FIND?
What is the relation between the areas of triangle abd and triangle bcd ?
SOLUTION:
- BD is angle bisector of Angle b
- AB / BD = BC /CD
- 9/ AD = 12/CD
- AD /CD = 9/12 = 3/4
LET SAY BE PERPENDICULAR TO AC
AREA OF TRIANGLE ABD = 1/2 * AD * BE = 3
AREA OF TRAINGLE BCD 1/2 * CD * BE 4
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