Question

In triangle ABC, AB=AC and AD perpendicular to BC. Prove that D is the midpoint of BC

Answer 1

Answer:

In triangle Δ ADB and Δ ADC

 AD =DA  (COMMON)

 ∠ADB =∠ADC (90° EACH)

 AB = AC   (GIVEN)

THEREFORE ΔADB≅ΔADC

BD =DC(CPCT)