Question

plz answer the above question .......APPROPRIATE ANSWER ONLY..........I will mark u as brainliest.....OKAY!!!!!

Answer 1

Let the force of smaller magnitude be A and the force of larger magnitude be B.

here,it is clearly given that the resultant force is R perpendicular to small force. hence, we can say that b is the hyopetenuse .

therefore, b² = R² + A²
=> R² = b² - A²
= 8²
= 64 .......................... ( 1 ).

here, it is also given that
A + B = 16 
therefore , B = 16 - A ..........................( 2 ).

Now, by substituting ( 2 ) in ( 1 ).we get,

( 16 - A ) ²- A² = 64
=> 256 - 32A + A² - A² = 64
32A = 256 - 64 = 192
A = 192 / 32 
= 6

hence, we get the result
B = 16 - A = 16 - 6 = 10

therefore, the magnitude of the two vectors are 6 and 10.