Question

in triangle ABC, AB=BC =10cm,AC= 12 cm .find it's area​

Answer 1

Answer:

THE ANSWER IS 54.5 CM

Step-by-step explanation:

GIVEN THAT ,

AB AND BC = 10

AC = 12 CM

SO , THIS IS ISOSCELES TRIANGLE

THE BASE OF THE TRIANGLE IS 12 CM AND THE OTHER TWO SIDES

MEASURE 10 CM .

JOIN B PERPENDICULAR TO AC DIVIDING IT INTO TWO EQUAL PARTS AND MARK IT AS D .

IN THE TRIANGLE ADB ,

THE BASE AD = 5 CM

THE HYPOTENUSE = 12 CM

( PERPENDICULAR ) ^ 2 = ( 12 CM ) ^2 - ( 5 CM )^2

                               = 144 - 25

                               = UNDER ROOT 119

                               = 10.90 CM.

THUS , THE HEIGHT OF THE TRIANGLE IS 10.90 CM

AREA OF AN ISOSCELES TRIANGLE = BASE * HEIGHT / 2

                                                              = 10 * 10.90 / 2

                                                              = 54.5 CM

THUS, THE AREA OF TRIANGLE IS 54.5 CM