the present age of the father is four times that of his son . 20 years hence the age of father will be twice the age of the son . find their present ages with explanation
Answers
Answered by
12
Answer :-
Given :-
- Present age of father is four times his son.
- After 20 years age of father will be twice the age of son.
To Find :-
- Present age of father and son
Solution :-
Let the present age of son be x
Present age of father = 4x
Age after 20 years :-
→ Son's age = x + 20
→ Father's age = 4x + 20
According to the question :-
→ 2( x + 20 ) = 4x + 20
→ 2x + 40 = 4x + 20
→ 4x - 2x = 40 - 20
→ 2x = 20
→ x = 20 / 2
→ x = 10
Age of son = 10 years
Age of father = 40 years
Answered by
0
Answer:
son's age =10 ,father's age =40
Step-by-step explanation:
let the son's age be x
and father's age be y
20 years hence son's age =x+20
father's age =y+20
y+20=2(x+20)
y+20=2x+40
2x-y+20=0----------------------------(1)
present,
y=4x-----------------------------------(2)
using 2 in 1,
2x-4x+20=0
-2x=-20
x=20/2
x=10
y=4*10
y=40
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