In triangle abc,AE,BF,CDare the three altitudes in the ratio of CD:AE:BF=2:3:4 then the ratio of AB:BC:AC
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Answer:
Given:△ABC,AD,BEandCFarealtitudesdrawnonthesidesBC,CAandABrespectively
AD:BE:CF=2:3:4
LetAD=2x,BE=3x,CF=4x
Areaof△ABC=
2
1
×BC×AD
=
2
1
×CA×BE
=
2
1
×AB×CF
⇒BC×AD=CA×BE=AB×CF
⇒2xBC=3xCA=4xAB
⇒2BC=3CA=4AB
⇒
6
BC
=
4
CA
=
3
AB
[Dividingby12]
⇒AB:BC:CA=6:4:3
Henceoption(B)iscorrectanswer
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