Question

in triangle abc and triangle d e f ab equals to df and Angle A equal to angle d by SAS exam which one condition is necessary to show that triangle ABC is congruent to triangle d e f​

Answer 1

Answer:

AC = DE  

Δ ABC  ≅ ΔDFE

Step-by-step explanation:

Δ ABC  &  ΔDEF

GIVEN

AB     = DF

∠A = ∠D

For Both Triangles to be congruent

as per SAS ( Side Angle Side)

AC = DE   is Necessary

=> Δ ABC  ≅ ΔDFE