in triangle abc, angle acb=90. she CD is perpendicular to side AB and she CE is angle bisector of angle acb. prove that AD/BD = AEsquare/BEsquare
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where did d come from
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This is from the chapter triangles isnt it??
Answer -
Consider triangle ACD and Tri. BCD
ang.ACD = ang.DCB (angle bisector)
CD=CD (Common side)
ang.CDA =ang.CDB (Given each 90°)
tri.ACD congruent tri.BCD (ASA)
AD=BD (CPCT)
Hope you understand
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