in triangle ABC ,angle B=45,angle C=55 and bisector of angle A meets BC at point D,find angleADB and angle ADC
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in triangle ABC
angle A +angle B +angle C= 180°
angle A+45°+55°=180
angle A =180-90
angle A=90°
given that
bisector of angle A
angle =A/2=90/2=45°
more solutions In attachment
in triangle ABC
angle A +angle B +angle C= 180°
angle A+45°+55°=180
angle A =180-90
angle A=90°
given that
bisector of angle A
angle =A/2=90/2=45°
more solutions In attachment
Attachments:
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