Question

in triangle ABC, angle B= 90° and angle A is double angle C.find AB/AC

Answer 1

Angle A = 2x Angle C = x 2x + x = 90 So x = 30  Angle C = 30 Angle A = 60 This is a 30-60-90 triangle. Let side opposite to Angle C = c and so on. Side opposite to 30 degree = c  So by the property of 30-60-90 triangle, side opposite to 60 degree = (√3)*c/2 = AB Side opposite to 90 degree = c/2 = AC Thus AB/AC = √3  Hope this helps! :)

Answer 2

Answer:

above ans is correct.....