in triangle abc, angle c=90 then sin(a+b)
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Given : in triangle abc, angle c=90°
To Find : sin(a+b)
Solution:
In any triangle sum of all angles of triangle is 180°
Hence ∠a + ∠b + ∠c = 180°
∠c = 90° given
=> ∠a + ∠b + 90° = 180°
=> ∠a + ∠b = 90°
sin(a+b) = Sin (90°)
=> sin(a+b) = 1
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Answer is 1......……....
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