Question

in triangle ABC, if angle A is equal to ( 2x minus 5)° , angle B is equal to (5x + 5)° , angle C us equal to (3x + 50 )° then find the value of x ,angle A, angle B and angle C

Answer 1

Sum of all angles of triangle is 180

Therefore,

angle A + angle B + angle C = 180

(2x-5)+(5x +5)+(3x+50)=180

2x-5+5x+5+3x+50=180

2x+5x+3x-5+5+50=180

10x+50=180

10x=180-50

10x=130

X=130/10

X=13

Angle A=(2x-5)=2 x 13 -5=26-5=21

Angle B=(5x+5)=5 x 13+5=65+5=70

Angle C=(3x+50)=3×13+50=39+50=89

Answer 2

Step-by-step explanation:

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