in triangle abc P is a point on BC such that BP is to PC is equal to 3 is to 5 then area triangle ABP is to area of triangle ABC is
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Answer:9:25
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let 3:5 be 3x and 5x,so BP:BC=3x:8x(3x+5x)
ar(ABP)=1/2×b×h
=1/2×3x×h
ar(ABC)=1/2×b×h
=1/2×8x×h
ar(abp):ar(abc)=(1/2×3x×h)/(1/2×8x×h)
1/2 and h is cancelled so
3x:8x
which is 3:8.
HOPE IT HELPS
ar(ABP)=1/2×b×h
=1/2×3x×h
ar(ABC)=1/2×b×h
=1/2×8x×h
ar(abp):ar(abc)=(1/2×3x×h)/(1/2×8x×h)
1/2 and h is cancelled so
3x:8x
which is 3:8.
HOPE IT HELPS
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