Question

in triangle abc point Angle B = 90 ab = 4 cm BC = 3 cm then AC is equal to​

Answer 1

${ab}^{2} + {bc}^{2} = {ac}^{2}$
(3)^2 + (4)^2= (ac)^2
9 + 16=(ac)^2
(ac)^2=25
ac=5

Answer 2

In Triangle ABC

angle B=90deg.

by phythagorus theorem

AC^2=AB^2+BC^2

=4^2+3^2

=16+9=25

AC=√25

AC=5