Question

In triangle ABC, right-angled at B, if Cot A = √3 find the value of: (i) sin A cos C − cos A sin C

Answer 1

Step-by-step explanation:

cotA =√3

cotA=cot30°

A=30°

B=60°

sinA=sin30°=1/2

cosA=cos30°=√3/2

SinC=sin60°=√3/2

cosC=cos60°=1/2

sinA cosC - cosA sinC

=1/2*1/2 -√3/2*√3/2

=1/4 -3/4

= -2/4

= -1/2