In triangle ABC, seg DE || SEG BC. if twice area of triangle ADE = area of quadrilateral DBCE, find AB:AD. SHOW THAT BC = √3 d
Answers
Answered by
1
Step-by-step explanation:
3A(△ADE)=A(DECB)⟹A(△ABC)=4A(△ADE)
⟹
A(△ADE)
A(△ABC)
=4
In △ADE and △ABC, ∠DAE=∠BAC
DE∥BC, ∠ADE=∠ABC and ∠AED=∠ACB
⟹△ABC and △ADE are similar.
⟹
A(△ADE)
A(△ABC)
=(
DE
BC
)
2
⟹4=(
DE
BC
)
2
⟹
DE
BC
=
1
2
Hence, option D is correct.
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Answered by
0
Step-by-step explanation:
In triangle ABC, seg DE || SEG BC. if twice area of triangle ADE = area of quadrilateral DBCE, find AB:AD. SHOW THAT BC = √3 d
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