In triangle abc side BC is produced to d if angle abc equal to 40 and angle ACD equal to 120 then find angle a
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bd is a straight line
angle(acd+acb)=180
angle (120+acb)=180
angle (acb)=180-120
angle(acb)=60
according to triangle theorem
sum of all angles=180
angle(abc+bca+cab)=180
angle (40+60+cab)=180
angle (cab)=180-100
angle (cab)=80
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