Question

In triangle PQR, angle PQR=90° Find sin P and cos P.
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Answer 1

Step-by-step explanation:

Take the given trigonometric ratio as 13k equation (i). sin θ = 5/13 .. .(i) [Given] By using the definition write the trigonometric ratio of sin θ and take it as equation (ii). In right angled ∆PQR, ∠R = θ Let the common multiple be k. ∴ PQ = 5k and PR = 13k Find QR by using Pythagoras theorem. PR2 = PQ2 + QR2 … [Pythagoras theorem] ∴ (13k)2 = (5k)2 + QR2 ∴ 169k2 = 25k2 + QR2 ∴ QR2 = 169k2 – 25k2 = 144k2 ∴ QR = √(144k2) . . . [Taking square root of both sides] = 12k Read more on Sarthaks.com - https://www.sarthaks.com/850966/in-right-angled-pqr-q-90-r-and-if-sin-5-13-then-find-cos-and-tan

Answer 2

Answer:

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