In triangle PQR,points A,B and C are taken on PQ,PR, and QR respectively such that QC=AC and CR=CB.IF QPR=40 degree and then angle ACB is
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let pqr=x & brc=y then bcr= 180-2y & acq=180-2x and acb=180-(bcr + acq)
that is 2(x+y)-180 but x+y=140 therefore acb=280-180=100
that is 2(x+y)-180 but x+y=140 therefore acb=280-180=100
abhishekdhameja:
thanks
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