Question

in triangle pqr xy parallel qr px=x-2, xq=3x, py=x+2 andyr=9x. find the value of x

Answer 1

Concept Introduction: Quadratic equations are special equation.

Given:

We have been Given:

$p = x - 2 \\ q = 3x \\ y = x + 2 \\ r = 9x$

To Find:

We have to Find: The Value of

$x$

Solution:

According to the problem,

$\frac{3x}{x - 2} = \frac{x + 2}{9x} \\ 27 {x}^{2} = x(x - 2) + 2(x - 2) \\ 27 {x}^{2} = {x }^{2} - 2x + 2x - 4 \\ 26 {x}^{2} = 4 \\ {x }^{2} = \frac{4}{26} \\ x = \frac{2}{13 \sqrt{2} }$

Final Answer:

$x = \frac{2}{13 \sqrt{2} }$

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