Question

In triangleABC, AB = BC and in triangleACD, AD = CD. Prove
that angleBAD = angleBCD. (Hint: Join BD.)
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Answer 1

Given: AB =BC and AD = CD

To prove : AD = CD

Proof: in ∆ABCand ∆ADC

AB = BC. Given

CD = AD. Given

AC = CA Common

∆ABC congruent to ∆ ADC by SSS

So, AD = CD by CPCT