Chemistry, asked by arshdeep71584, 2 months ago

why all the bond length of sulphur -oxygen in sulphate ion are equal ​

Answers

Answered by gouravkuamrverma2
2

Answer:

SF4 has four bonded atoms and one lone pair. The five electron pairs around sulphur adopt trigonal bipyramidal geometry in which one position is occupied by a lone pair. ... The axial S-F bonds are bent slightly away from the lone pair. Hence, all the bonds in SF4 are not equivalent.

Answered by rahul123437
1

All the bond lengths of sulphur -oxygen in sulphate ions are equal due to their resonance.​

Explanation:

  • Electronic configuration of S is 1s2, 2s2, 2p6, 3s2, 3p4 .
  • The five electron pairs around sulphur adopt trigonal bipyramidal geometry in which one position is occupied by a lone pair.
  • In SO2 molecules, the observed bond lengths in the two S-O bonds are exactly the same.
  • The length is somewhere in between single and double bond length. It is because of resonance.
  • Actually, it is the reason behind SO2 is having a bent structure.
  • The molecule is having a resonance hybrid. Thus, both S−O bonds have equal length.
  • The structure of the sulfur dioxide molecule will have partial negative charges on the oxygen atoms and a partial positive charge on the sulfur atoms.

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