in two concentric circles a chord of length 24cm of larger circle becomes a tangent to the smaller circles whose radius is 5cm.find the
radius of larger circle.
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Answered by
7
Radius if smaller circle is 5
Chord length of larger circle is 24
if we draw the radius of smaller circle to the tangent it is dvided into half
so each part become 12
By Pythagoras theorem te radius of larger circle is 13
Chord length of larger circle is 24
if we draw the radius of smaller circle to the tangent it is dvided into half
so each part become 12
By Pythagoras theorem te radius of larger circle is 13
Answered by
17
Length of chord of larger circle = 24cm
radius of smaller circle = 5cm
So by joining the centre and point of tangent of smaller circle we get a radius of smaller circle of 5cm.
And which is perpendicular to tangent and so as it is chord so it will get bisected by radius
Now,
join one end of chord with the centre and that forms a right-angled triangle,
Now let's find the radius of larger circle by using pythagoras theorem.
let radius of larger circle be OA = ?
let radius of smaller circle be OL = 5cm
and Chord be AB = 24cm
So,
AL=12cm
OA^2= OL^2+AL^2
OA^2=25+144
OA^2=169
we get,
OA = 13cm
radius of larger circle is 13cm
radius of smaller circle = 5cm
So by joining the centre and point of tangent of smaller circle we get a radius of smaller circle of 5cm.
And which is perpendicular to tangent and so as it is chord so it will get bisected by radius
Now,
join one end of chord with the centre and that forms a right-angled triangle,
Now let's find the radius of larger circle by using pythagoras theorem.
let radius of larger circle be OA = ?
let radius of smaller circle be OL = 5cm
and Chord be AB = 24cm
So,
AL=12cm
OA^2= OL^2+AL^2
OA^2=25+144
OA^2=169
we get,
OA = 13cm
radius of larger circle is 13cm
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