Question

in what ratios does the line x-y-2=0 divides the line segment joining (3,-1) and (8,9)

plz plz answer it fast

Answer 1

let the ratio in which line divides the line joining two points be k:1

now according to section formula

X= 8k/k+1+3/K+1,
Y= 9K/k+1 - 1/K+1
 
NOW SUBSTITUTING THE VALUES Of x and y in equation

8k/k+1+3/K+1 -  9K/k+1 + 1/K+1 - 2 = 0

k = 2/3


  
 

Answer 2

Hey there!

Question:

In what ratio does the line x-y-2=0 divide the line segment joining the points A (3, -1) and B (8, 9)?

Answer:

Let the ratio be k:1.

And, point of intersection be (X,Y).

Now,

X = (m₁x₂ + m₂x₁) /( m₁ + m₂)

X = (k*8 + 1*3) / (k+1)

X = (8k + 3) /( k + 1)

And,

Y =  (m₁y₂ + m₂y₁) /( m₁ + m₂)

Y = ( k* 9 - 1*1) / (k+1)

Y = (9k-1)/(k+1)

Now,

Since, the point (X,Y) also lies on x - y - 2 = 0.

So, it will satisfy the given equation,

x - y - 2 = 0.

(8k+3)/(k+1) - (9k-1)/(k+1) - 2 = 0

⇒ (8k + 3 - 9k - 1)/ (k+1) = 2

⇒ -k +4 = 2k + 2

⇒ 4 = 2k+ k + 2

⇒2  = 3k

⇒ 2/3 = k

or, k = 2 / 3

Now,

Ratio = k : 1 = (2 / 3) : 1 = 2 : 3