Question

in what time will ₹160000 becomes ₹194481, if interest is 10% per annum compounded semi annually?

Answer 1

Answer:

4 years

Step-by-step explanation:

A=(1+R/200)^T

194481=160000(1+10/200)^t

194481/160000=(1+1/20)^t

194481/160000=(21/20)^t

(21/20)^4=(21/20)^t

t=4 years

Answer 2

Answer:

Time (n) = 2 years.

Step-by-step explanation:

          A= P (1+r/200)^2n            ....( semi-annually)

194481 = 160000 ( 1 + 10/200)^2n

194481/160000= (21/20)^2n

(21/20)^4 = (21/20)^2n

             4 = 2n

             n = 2       .....(Answer)

**Verification :-

      A = 160000 (1 + 10/200)^2*2

         = 160000 * (21/20)^4

         = 160000 * 21/20 * 21/20 * 21/20* 21/20

         = 21*21*21*21

      A = 194481      ....(verified)

Hope this helps!